Isoelectronic Question: Oxygen Ion and Isoelectronic Species Comparison

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SUMMARY

The discussion centers on identifying which ion is isoelectronic with the oxygen ion (O2-). The participants conclude that the sulfur ion (S2-), chlorine ion (Cl-), sodium ion (Na+), and argon (Ar) are candidates for comparison. Ultimately, it is established that the correct answer is the chloride ion (Cl-) and argon (Ar), as they share the same electron configuration of 18 electrons, while the sulfur ion does not match the oxygen ion's electron configuration.

PREREQUISITES
  • Understanding of isoelectronic species
  • Knowledge of electron configurations
  • Familiarity with common ions: O2-, S2-, Cl-, Na+, Ar
  • Basic principles of atomic structure
NEXT STEPS
  • Study the concept of isoelectronic species in detail
  • Learn about electron configurations for various ions
  • Explore the periodic table's trends related to ionization and electron affinity
  • Investigate the implications of isoelectronicity in chemical bonding
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Chemistry students, educators, and anyone interested in atomic structure and electron configurations will benefit from this discussion.

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Homework Statement



which of the following is isoelectronic with the oxygen ion

sulfur ion
chlorine ion
sodium ion
argon

Homework Equations





The Attempt at a Solution



i think the answer is the sulfur ion because it has the same number of valence electrons. is this the correct:::::::::::::

i figured it out it's because they have the same electron configurations
ty
 
Last edited:
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Isoelectronic does not refer to equal number of valence electrons, but rather equal number of electrons (and hence equal electron configurations).
i figured it out it's because they have the same electron configurations
The electron configurations of a sulfur ion and an oxygen ion are not the same.
 

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