It is possible to solve this question without F given to me?

  • Thread starter Femme_physics
  • Start date
In summary, you need to find the equation for F that when solved, will give you the e in the problem. You may have forgotten to replace 2/h by h/2 in your equation, which would have resulted in a different result. Once you have the equation for F, you can cancel out the friction forces using the formulas you should have just added.
  • #1
Femme_physics
Gold Member
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Problem Statement

http://img715.imageshack.us/img715/6372/galde.jpg


A wheel is set upon a shaft in a small gap. At point C of the wheel is acting horizontal force F, as described in drawing. The needed measurements are given in a general manner. The friction coeffecient between the wheel and shaft is mieu. What's the max distance (e) where there would still be forward horizontal movement of the wheel on the shaft (presuming F remains constant)

Homework Equations





The Attempt at a Solution



I've no clue, I can write the equations, but what's the point if F can be a million Newtons of 1 Newton?

http://img10.imageshack.us/img10/767/muchraz1.jpg

http://img707.imageshack.us/img707/6277/muc2.jpg
 
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  • #2
Good evening Fp! :smile:

Good you already got these equations! :cool:

Don't worry about the size of F, we'll get to that later.

First, let's try to complete the set of equations.
Then, let's see if we can quickly eliminate a couple of variables.

Your sum of moments has the wrong distance for F.
Can you correct that?

And I'm missing the equations that relates friction to normal force.
Can you add those?Running ahead and assuming you got the equations, can you eliminate the friction forces?
That is, replace them by the formulas you should have just added?
 
  • #3
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  • #4
Don't be discouraged! :wink:

Let's just see what happens if we move on.

First, though, you adjusted the distance of the force F, but you have the wrong amount: you wrote 2/h, but it should be h/2.

Then, can you go on eliminating unnecessary variables?
(I'm thinking of eliminating first NA, and then NB.)

Then you should be left with one equation with only F and e.
When we have that, we'll see if there is something else you can do! :smile:
 
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  • #6
You forgot to replace 2/h by h/2.

And can you simplify the expression?
(Get rid of the round thingies, calculate the numbers as far as possible, and match up similar parts?)
 
  • #8
You didn't get rid of the round thingies properly.
(Do you know the "rules" to get rid of round thingies? :wink:)

Edit: just noticed, your distance for F is still not right.
 
  • #10
As I said, your distance for F is still wrong (in a previous scan).
It should be (e + h/2) and not (e - h/2).

After you have corrected that, you should divide your equation by F.
(Remember the Wheatstone Bridge, pardon me, "Electrobob!" where you did something similar? :wink:)
 
  • #11
Can you scoop me up the answer since I'm about to turn in and the test is tomorrow morning? The test is with open material so I can print it in case there'll be anything similar. I know it's a lot to ask I'll understand if you refuse!
 
  • #12
We're not supposed to give out full solutions!

That is, unless the OP has shown significant work. :approve:

Ok.

Your last equation should be (with corrected distance for F):
[tex]-F \cdot (e + \frac h 2) + \frac F {0.4} \cdot b + \frac F {0.4} \cdot 0.2 \cdot h = 0[/tex]

Simplifying:
[tex]-F \cdot e - F \cdot \frac h 2 + \frac F {0.4} \cdot b + F \cdot \frac h 2 = 0[/tex]

Canceling equal and opposite terms:
[tex]-F \cdot e + \frac F {0.4} \cdot b = 0[/tex]

Dividing by F:
[tex]-e + \frac b {0.4} = 0[/tex]

Since the problem asked for e, solve for e:
[tex]e = \frac b {0.4}[/tex]

Tadaaaa! :smile:

(Give me a kiss? :blushing:)
 
  • #13
Wait, manual says "e" equals 120mm. Is that a mistake? But then again, I now see I wrote "mistake" in this page of the solutions heh. See! That's what confused me. Gah! I thought this was a full numeral solution, which is why I figured it was impossible. Now I get it! :DThanks! *smooches*
 
  • #14
Aha, we missed that b was given as 48 mm!
Fill it in and you get your e=120 mm. :smile:

Still, the clue is that F cancels when you work it out.
This should make some intuitive sense.

If you push twice at hard, all the forces (normal forces and friction forces) will also be twice as big.
For the situation where the system is in equilibrium, it does not matter how big F is!


*smooches* :blushing:
 
  • #15
I don't see how F cancels out, frankly, but I don't really have time to work it out

Thanks
 

Related to It is possible to solve this question without F given to me?

1. Can you explain how it is possible to solve a question without having F given to you?

Yes, it is possible to solve a question without having F given to you by using other variables, equations, and information provided in the question. This requires critical thinking and problem-solving skills.

2. What are some strategies or techniques for solving a question without F given?

Some strategies include breaking down the question into smaller parts, using substitution or elimination methods, and using relevant formulas or equations to solve for the unknown variable.

3. Is it necessary to have all variables given in order to solve a question accurately?

No, it is not necessary to have all variables given to solve a question accurately. However, having more information can make the problem easier to solve and provide a more precise answer.

4. Are there any limitations or challenges when solving a question without F given?

Yes, there may be limitations or challenges such as not having enough information to accurately solve the question, or the solution may be more complex and require advanced mathematical skills.

5. Can you provide an example of a question that can be solved without F given?

Sure, for example, if we have the equation A + B = C and we are given the values for A and B, we can solve for C without knowing the value of F. We can rearrange the equation to solve for C, which would be C = A + B - F.

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