Calculating Force and Motion on an Inclined Plane

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Homework Help Overview

The discussion revolves around a physics problem involving a body moving up an inclined plane with a constant force and the effects of friction. The participants are tasked with calculating the force acting on the body and analyzing its motion under different conditions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of acceleration and the application of Newton's laws. There are questions about the correct interpretation of the problem statement and the implications of the body’s velocity decreasing. Some participants express uncertainty about the formulas being used and the dimensions of acceleration.

Discussion Status

The discussion is active, with participants providing feedback on each other's calculations and reasoning. Some guidance has been offered regarding the formulas and the interpretation of the problem, but there is no explicit consensus on the final answers yet.

Contextual Notes

Participants note potential misunderstandings regarding the problem's parameters, such as the relationship between initial and final velocities and the nature of acceleration. There is also mention of homework constraints and the need for careful consideration of rounding in calculations.

  • #31
Well, OK. So -Fk+F = 456.837 N. What is Fk?

ehild
 
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  • #32
Fk is 1.879 [kN]

Which means that I'm an idiot

Because I didn't translate KiloNewtons to Newtons heh:-p

You got me :wink:

Thanks :smile:
 
  • #33
There were fewer mistakes in your posts if you typed in the calculations. And they were easier to read.

ehild
 
Last edited:
  • #34
Still off, if I convert everything to Newton it turns out 1420.28 [N] whereas the manual says 4840.87 [N]

Can you help and tell me what did I miss?
 
  • #35
It seems to me that you ignored a force. Maybe it is there, but I can hardly read your webcam picture. Would you please type in the solution, as everybody else do? ehild
 
Last edited:
  • #36
As far as I can tell, you have the right answer.

Are you sure all the problem data correct?
Like that you have an initial speed of 6 m/s decreasing to 3 m/s?
 
  • #37
I will write the full question for reference

http://img846.imageshack.us/img846/6564/samemethod.jpg



An body whose weight is W proceeds upwards on an incluned plane, slanted to the horizontal axis at angle alpha.
The force (F), acting on the body parallel to the inclined plane, remains constant during the entire action. The friction friction coeffecient between the body and surface is μ.

A) Calculate the force (F) acting on the body, if in the motion of the body its velocity decreases from 6 m/s to 3 m/s

B) What is the work done in this segment?
 
Last edited by a moderator:
  • #38
ehild said:
There were fewer mistakes in your posts if you typed in the calculations. And they were easier to read.

ehild

I just noticed that post. Well, it's tons more time-consuming to do it via typing. I'll try though to be as clear as I can, and show it typed whenever I can.
 
  • #39
Good morning Fp! :smile:

No mistake. I believe your answer is correct.
(Unless ehild thinks otherwise. :wink:)
 
  • #40
Femme_physics said:
I just noticed that post. Well, it's tons more time-consuming to do it via typing. I'll try though to be as clear as I can, and show it typed whenever I can.

Well, it is very difficult to read your handwriting, but your comfort is the first.

Have you found the missing force? Hint: look at the solution of the previous problem.

ehild
 
  • #41
I like Serena said:
Good morning Fp! :smile:

No mistake. I believe your answer is correct.
(Unless ehild thinks otherwise. :wink:)

Neat :smile: ! So the work done is just

Fk x AB = 1879 x 30 = 56370 [N x m]Yes?
 
  • #42
ehild said:
Well, it is very difficult to read your handwriting, but your comfort is the first.

Have you found the missing force? Hint: look at the solution of the previous problem.

ehild

Well, yes, if I corrected the kN -> N thing it turns out 1420.28 [N]

I figured that was right, that's what I thought ILS was saying

Well, it is very difficult to read your handwriting, but your comfort is the first.

I'll try be clearer then. I normally write it big with a big marker, in this case though I can see why it's difficult. If you'll ask me to redo it typed I will
 
  • #43
I like Serena said:
No mistake. I believe your answer is correct.
(Unless ehild thinks otherwise. :wink:)


I see only the applied force and friction.

ehild
 
  • #44
ehild said:
I see only the applied force and friction.

ehild

You're right, so Fp's answer is wrong after all.
(Good that I made an exception clause! :smile:)
 
  • #46
Good! :smile:
 

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