Iterative integration in several variables

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SUMMARY

This discussion centers on the validity of iterative integration in multiple variables, particularly in the context of divergent integrals. The participant argues that one can perform iterative integration by fixing variables and applying Hadamard's finite part integral definition to regularize results. The conversation also touches on introducing regulators, such as ((x+a)((y+b)(z+c))^{-s}, to render integrals convergent before taking limits. The consensus emphasizes that the validity of these manipulations is contingent on the mathematical context and objectives.

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  • Understanding of multiple integrals in calculus
  • Familiarity with Hadamard's finite part integral definition
  • Knowledge of analytic continuation techniques
  • Concept of divergence and regularization in mathematical analysis
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  • Research Hadamard's finite part integral definition in detail
  • Study the principles of analytic continuation in complex analysis
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Physicists, mathematicians, and researchers dealing with integrals in multiple variables, particularly those focused on regularization and divergence in mathematical analysis.

zetafunction
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as a physicist , there are some integrals in several variables that are DIVERGENT

in order to regularize them i argue that for any integral in several variables

[tex]\int_{V} f(x,y,z)dV[/tex]

you can always perform an interative integration (you integrate in variable 'x' for example keeping the others variables as constant and then you regularize the result in each variable by using the Hadamard's finite part integral definition)

but is this valid ?? .. even for a divergent integral (let us suppose we introduce a cut-off so the integral is rendered finite and then we take the cut-off limit --> oo ) is this valid we can perform an integral in several variables by doing an interation of one dimensional integrals ??

let us suppose i introduce the regulators [tex]((x+a)((y+b)(z+c))^{-s}[/tex]

for a big 's' so the integral is convergent and then i take the limit (by analytic continuation ) to s -->0
 
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zetafunction said:
but is this valid ??
Divergence in mathematics cannot be renormalized away. So whether a manipulation is "valid" depends largely on the background and purpose.
 

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