Jackson 1.12 & 1.13: Prove Thomson's & Insulated Conductor Theorem

Click For Summary
SUMMARY

The discussion focuses on proving Thomson's theorem and the implications of introducing an insulated conductor in electrostatic scenarios. Specifically, it addresses two problems from Jackson's textbook: Problem 1.12 asserts that the electrostatic energy is minimized when conducting surfaces are equipotential, while Problem 1.13 states that adding an uncharged insulated conductor reduces the electrostatic energy. The participants clarify that the conducting surfaces are not connected and discuss the nature of the insulated conductor, confirming that its volume does not significantly impact the problem.

PREREQUISITES
  • Understanding of electrostatics and potential theory
  • Familiarity with Jackson's "Classical Electrodynamics" textbook
  • Knowledge of conducting surfaces and equipotential concepts
  • Basic principles of electrostatic energy calculations
NEXT STEPS
  • Study the implications of equipotential surfaces in electrostatics
  • Research the concept of electrostatic energy minimization in conducting systems
  • Explore the effects of introducing conductors in electrostatic fields
  • Review problem-solving techniques for electrostatics in Jackson's textbook
USEFUL FOR

Students and professionals in physics, particularly those studying electrostatics, as well as educators looking for insights into teaching concepts related to conducting surfaces and electrostatic energy.

nctweg
Messages
11
Reaction score
3

Homework Statement



1.12 -
Prove Thomson's theorem : If a number of conducting surfaces are fixed in
position and a given total charge is placed on each surface, then the electrostatic
energy in the region bounded by the surfaces is a minimum when the
charges are placed so that every surface is an equipotential.

1.13 -
Prove the following theorem: If a number of conducting surfaces are
fixed in position with a given total charge on each, the introduction of an
uncharged, insulated conductor into the region bounded by the surfaces
lowers the electrostatic energy.

The Attempt at a Solution



So I haven't actually started them yet because I don't quite understand the geometry I'm being asked about. Note - I am not really looking for help on how to do the problems (at least not yet, I want to give it at least a week before giving in).

My questions are simple and perhaps dumb; are these conducting surfaces connected? It says that there is a region bounded by the surfaces but if that were the case and they were conducting, wouldn't they just end up forming some kind of closed shape with the charge spread throughout (rather than, as the problem indicates, each surface having Q total charge). My other thought is that Jackson's just referring to a general region that's between the surfaces but not necessarily closed but I really can't tell which is what the question is asking about.

Also in problem 1.13, is the insulated conductor a surface or does it have volume? (Or does it not make a difference?). Are we just approximating the insulation as being thin enough that it makes no difference?

Thanks for the help!
 
Physics news on Phys.org
The surfaces are not connected.
 
  • Like
Likes   Reactions: nctweg
Okay, thanks for confirming my stupid question. I figured as much but I did want to check first.
 

Similar threads

Replies
3
Views
6K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
13
Views
4K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
12K
  • · Replies 1 ·
Replies
1
Views
6K