Juggler Problem: Solving Kinematics for Ceiling Height

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A juggler can transfer a ball from his left hand to his right hand in 0.20 s. If he is juggling 5 balls and releases them from a height of 1.5 m, what is the minimum height of the ceiling? How much higher should the ceiling be if he wants to juggle 6 balls ?

How are we going to solve this? If we use kinematics equations, we could problem get through it, but I am not sure how to.
 
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Doesn't seem like there's enough information regarding catch and throw times for the juggled balls. If the transfer from left to right hand is a toss (what most jugglers do), then it's possble for the juggler to do the left hand transfer toss before the right hand does the upwards toss, using the .2 second window of transfer toss time to switch between the upward toss and catching the ball from the transfer toss. Same goes for the left hand catching the next ball during the .2 second window transfer toss time. This would reduce the time between tosses. On the other hand, the time between tosses could be greater than the .2 second toss window time.

Perhaps the idea is to assume throw and catch time overhead is effectively zero, so that the time between all tosses is .2 seconds.
 
All the information required to solve the problem is present, provided one makes some common-sense assumptions, including that 0.20 s is the time from catching a ball with one hand to throwing the same ball with the other. Another assumption would be that he can throw one ball at the same moment he catches the one behind it.

Thus, 0.20 s is simply dwell time at the bottom, as well as the time between each of the balls in flight. The only kinematic equation required is the one for the vertical component.
 
This might help in the visualization of the problem: http://www.flasharcade.com/arcade-games/juggling-simulator-game.html :)
 
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