Just Checking - Calculating Angular Diameter of Moon

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SUMMARY

The discussion focuses on calculating the Angular Diameter of the Moon using a digital SLR camera and calibration images. The formula for plate scale, defined as plate scale = s/θ, is utilized, where 's' represents a fixed measurement on the image and 'θ' is the angle from the lens to the object. The consensus confirms that θ should be measured in arcminutes for the final calculation, which yields an angular diameter of 29.0 arcminutes or 0.54 degrees. The approach is validated through practical application and the small angle assumption.

PREREQUISITES
  • Understanding of angular measurements (degrees, arcminutes)
  • Familiarity with digital SLR camera settings and image calibration
  • Basic knowledge of trigonometry and geometry
  • Experience with the small angle approximation
NEXT STEPS
  • Research the small angle approximation and its applications in astronomy
  • Learn about image calibration techniques for astrophotography
  • Explore advanced methods for calculating angular diameter using different celestial objects
  • Investigate the effects of pixel size on measurements in digital imaging
USEFUL FOR

Astronomy enthusiasts, astrophotographers, and students studying celestial measurements will benefit from this discussion, particularly those interested in calculating angular diameters and understanding image calibration techniques.

TFM
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As part of an on-going project, I have to calculate the Angular Diameter of the moon. This is to be done using a digital SLR Camera. I have some pictures, as well as some calibration images (a ruler a fixed distance away). I am pretty sure I need to use the formula:

[tex]plate scale = \frac{s}{\theta}[/tex]

where s is a fixed measurement on the image, and theta is the angle from the lens to either side of s of the actual object.

Therefore I need to work out the angle to the ruler (see diagram), and use that and the pixel size of the ruler to calculate the Plate Scale. then use plate scale and pixel size of moons diameter to calculate the anbgular diameter.

Does this seem right?

Also, does theta have to be in radians or arcminutes? (I think its arcminutes)

TFM
 

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I would use arcmin for your final answer. Your approach is correct. To help keep it in your head correctly, just draw yourself a long triangle. It's as simple as solving for the angles in it and you can use the small angle assumption on it (google that if you don't know what it is...).
 
I've tried it out and it does work using arcminutes - it gives me an answer of 29.0arcminutes which converts to 0.54 Degrees.

Thanks,

TFM
 

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