Just looking for confirmation for a torque calculation

[pete94857]

The correct formula is $KE = \frac{1}{2} \times I \times {\omega_f}^2$

Note that the $\omega_f$ is squared.

If you do not apply the factor of $\frac{1}{2}$ and do not square $\omega_f$ then the result will be angular momentum. We use the symbol "L" for angular momentum: $L = I \times \omega_f$.


In the car problem, the same applies. The correct formula is $KE = \frac{1}{2} \times m \times v^2$

If you do not apply the factor of $\frac{1}{2}$ and do not square $v$ then the result will be momentum. We use the symbol "p" for momentum: $p = m \times v$

Notes taken thank you