Just to double check, Linear Momentum

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SUMMARY

The discussion centers on a physics problem involving a bullet and a wooden block, specifically analyzing the collision dynamics. A bullet with a mass of 0.1 kg is fired at a speed of 250 m/s into a stationary block weighing 15 kg. The calculated velocity of the block with the embedded bullet immediately after impact is 20.412 m/s, determined through the conservation of momentum. The discussion also raises the question of whether the collision is elastic, prompting further exploration of kinetic energy conservation.

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  • Understanding of linear momentum and its conservation principles
  • Knowledge of kinetic energy calculations
  • Familiarity with elastic and inelastic collisions
  • Basic algebra for solving equations
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  • Study the principles of conservation of momentum in collisions
  • Learn about elastic vs. inelastic collisions and their characteristics
  • Explore kinetic energy calculations in different types of collisions
  • Investigate real-world applications of momentum conservation in physics
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Homework Statement


A bullet of mass 100 grams is fired horizontally into a 15 kilogram block of wood resting on a horizontal surface and embeds itself in the block. If the muzzle speed of the bullet is 250 meters per second, what is the velocity of the block containing the embedded bullet immediately after the impact?

Given:
Bullet with weight of 0.1kg (100g) fired horizontally with a velocity of 250 m/s
Wooden block at rest weighing 15kg

Homework Equations


(1/2)(mass)(velocity^2) = KE

The Attempt at a Solution


(1/2)(0.1kg)(250m/s^2) = 3125 Joules <-- Kinetic energy of bullet
Convservation of Energy
(1/2)(15kg)(v^2) = 3125
V^2 = 416.666...
V = 20.412 m/s
 
Physics news on Phys.org
Welcome to PF;
Is the collision of the bullet and block elastic? i.e. is kinetic energy conserved?
Check by conservation of momentum.
 

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