Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y = x^2 +1 , y = 9-x^2: about y = -1
The Attempt at a Solution
I used disks. I said that r = 1 + ((9-x^2)-(x^2 +1 )) = 9 - 2x^2
So my integral all together is
V = ∏ ∫ (9 - 2x^2)^2 dx from [-2,2]
Does this set up look correct.?