Kate's Chances of Winning a 5 Match Tennis Tournament

Click For Summary
SUMMARY

The probability of Kate winning a 5-match knockout tennis tournament, given her individual match win probability of 80%, is calculated as 0.8^5, resulting in a 33% chance of winning the tournament. When considering the probability of her winning the tournament after winning her first three matches, the calculation simplifies to the same 33%, as winning all five matches encompasses winning the first three. The intersection of winning all five matches and winning the first three does not alter the overall probability, confirming that the two scenarios are equivalent.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with knockout tournament structures
  • Knowledge of exponentiation in probability calculations
  • Ability to interpret conditional probabilities
NEXT STEPS
  • Study advanced probability theory, focusing on independent events
  • Learn about combinatorial analysis in tournament settings
  • Explore the implications of conditional probability in sports analytics
  • Investigate the application of probability in decision-making processes
USEFUL FOR

Mathematicians, statisticians, sports analysts, and anyone interested in understanding probability in competitive scenarios.

Bushy
Messages
40
Reaction score
0
The Probability of Kate winning a tennis match is 80%. If she enters a 5 match knockout tournament, find the chance of her:

a) winning the tournament:


Is simply 0.8^5 = 33%

b) winning the tournament given she wins her first three games:

Is the intersection of the two over the probability she wins the first three = 0.8^5 * 0.8^3 / 0.8^3 = the same as part a?
 
Physics news on Phys.org
Bushy said:
The Probability of Kate winning a tennis match is 80%. If she enters a 5 match knockout tournament, find the chance of her:

a) winning the tournament:


Is simply 0.8^5 = 33%

Keep your answer exact please. $\displaystyle \begin{align*} \left( \frac{4}{5} \right) ^5 = \frac{1024}{3125} \end{align*}$.

b) winning the tournament given she wins her first three games:

Is the intersection of the two over the probability she wins the first three = 0.8^5 * 0.8^3 / 0.8^3 = the same as part a?

No, winning all five and winning the first three is equivalent to simply winning all five. So the intersection is simply what you found in part (a).
 
Prove It said:
No, winning all five and winning the first three is equivalent to simply winning all five. So the intersection is simply what you found in part (a).

Therefore 0.8^3 / 0.8^3 = 1 ?
 
Bushy said:
Therefore 0.8^3 / 0.8^3 = 1 ?

NO! The top is the probability of winning all FIVE!
 
Well that would give a neat answer, but aren't we saying the intersection of winning the first three and winning all five should be winning the 1st three?
 
Bushy said:
Well that would give a neat answer, but aren't we saying the intersection of winning the first three and winning all five should be winning the 1st three?

No, the only way it is possible to do both "winning all five games" and "winning the first three games" is to win all five games!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K