Kernel and images of linear operator, examples

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SUMMARY

The discussion focuses on finding the kernel and range of the linear operator defined on the space of polynomials P_3, specifically the operator L(p(x)) = x*p'(x). The kernel is determined by solving the equation xp'(x) = 0, which identifies the values of x that yield zero output. The range consists of functions generated by L(p(x)), which can be expressed as the span of the set {(x^2, x)}. This analysis clarifies the definitions and computations necessary for understanding linear operators in polynomial spaces.

PREREQUISITES
  • Understanding of linear operators in the context of polynomial spaces
  • Knowledge of differentiation and its application to polynomials
  • Familiarity with the concepts of kernel and range in linear algebra
  • Basic proficiency in polynomial expressions and their manipulations
NEXT STEPS
  • Study the properties of linear operators in vector spaces
  • Learn about the Rank-Nullity Theorem and its implications for linear transformations
  • Explore examples of kernels and ranges for different types of linear operators
  • Investigate the relationship between polynomial degree and the dimensions of kernel and range
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Students of linear algebra, particularly those studying polynomial functions, educators seeking clearer explanations of linear operators, and anyone looking to deepen their understanding of kernel and range concepts.

Niles
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Homework Statement


If I e.g. want to find the kernel and range of the linear opertor on P_3:

L(p(x)) = x*p'(x),

then we can write this as L(p'(x)) = x*(2ax+b). What, and why, is the kernel and range of this operator?

The Attempt at a Solution


The kernel must be the x's where L(p'(x)) = 0, so do I just solve the equation?

The range is the elements that span the polynomial, so it is span{(x^2,x)}?

Hope you can help.
 
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Niles said:

Homework Statement


If I e.g. want to find the kernel and range of the linear opertor on P_3:

L(p(x)) = x*p'(x),

then we can write this as L(p'(x)) = x*(2ax+b). What, and why, is the kernel and range of this operator?

The Attempt at a Solution


The kernel must be the x's where L(p'(x)) = 0, so do I just solve the equation?
Well, L(p)= 0, not L(p'). You must solve xp'(x)= 0 for all x.

The range is the elements that span the polynomial, so it is span{(x^2,x)}?
If every member of P_3 can be written as p(x)= ax^2+ bx+ c, then p'(x)= 2ax+ b and so L(p(x))= 2ax^2+ bx. That set of functions is the range. Since a can be any number, so 2a can be any number.
 
The kernel:
2ax^2+bx = 0 <=> 2ax+b=0 - is this the kernel, or do I have to isolate x first?

The range:
Ok, so the range is just the set of functions we get from L(p(x))?

I know these are quite basic subjects in linear algebra, but it is explained so poorely in my book and they've only spent ½ page giving definitions - nothing else.
 

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