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Kernel "stable under": is my interpretation correct?

  • Thread starter _Andreas
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[SOLVED] Kernel "stable under": is my interpretation correct?

1. Homework Statement

A1, A2, A3,..., Ar are endomorphisms. W is the kernel of Ar - lambda*I, where lambda is the eigenvalue of Ar. W is stable under A1, A2, A3,..., Ar-1. Question: does "stable under" equal "closed under", and is the following interpretation of this stability correct?

For all elements u in W, Aku is an element in W.​
 
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Answers and Replies

Dick
Science Advisor
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I believe so. I can't think what else it would mean.
 
144
1
I believe so. I can't think what else it would mean.
Ok, thanks!
 

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