Kind of a challenge(for me i guess)

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Homework Help Overview

The discussion revolves around a physics exam that a dentistry student is preparing for, expressing difficulty with specific questions related to forces, energy, and motion. The subject area includes concepts from mechanics and energy conservation.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the student's specific questions, with some suggesting to consider the forces acting on an object and applying energy conservation principles. There are discussions about potential and kinetic energy, as well as the importance of understanding the problem setup.

Discussion Status

Some participants have offered guidance on how to approach the questions, while others express frustration with the pace of the discussion. The student has indicated a desire for quicker solutions but is also encouraged to engage with the material for better understanding.

Contextual Notes

The student is under time pressure to prepare for an upcoming exam and has expressed a lack of interest in physics, viewing it as less relevant to their future career in dentistry.

wicked
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hello everyone , I am a newbe here ,im a dentistry student ,foundation year ,to pass this year I am required to pass physics ,i actualy suck at physics lol ,well i need any of you to solve this exam for me please it should be eazy for any member here i guess(i heard everyone here is really good) the catch is i need it by tomorow ,so if this is posible its much apreciated ,thanx a lot :rolleyes:

here is the link..


http://www.yousendit.com/transfer.php?action=download&ufid=40BD63384601883C"
 
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I'm only new here myself, but I'm fairly certain that's not how it works...there's certainly not many people here who will solve a whole exam for you. Are there any specific questions that you're having trouble with?
 
Indeed, the challenge is yours...

Show some working!
 
yea spesific Qs ,

from file 2 , Q8

from multiple choice Q6
^^havin problems with thos ,
thos are the important ones , but ill be glad if u can solve the last Qin file 2btw , I am not doing that just to get the answers , this is just a practic exam ,the real exam is similar 2 it on saturday ,so i actualy need to learn how to get the answers , anyway ill apreciate it if u can solve any of the 3 Q i mentiond up
 
Hello wicked,

as for Question 8 in the second file:

a) well, try to imagine which forces are acting on you right now (probably sitting in a chair), then there is another force which is responsible for the deceleration of the block in your problem.

b) apply the energy theorem

c) start with Newton's second law of motion; I'm not sure why the text states the coefficient of kinetic friction [tex]\mu_k=0.33[/tex] while the sketch says [tex]\mu_k=0.30[/tex]

Regards,

nazzard
 
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thats just a printing mistake , thanks a lot
 
but i dun get it in part A i need s to solve the prob ,and in part C they are askin me for s
 
wicked said:
thats just a printing mistake , thanks a lot

You're welcome! :smile: Feel free to post your results. Then on to the next question! :wink:

wicked said:
but i dun get it in part A i need s to solve the prob ,and in part C they are askin me for s

A small hint: the block has a certain kinetic energy at the bottom of the ramp before it enters the rough part. After the process of deceleration the block does not move, hence the kinetic energy is zero at the end. Where did it go?
 
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turned to potential energy?
(remeber i suck at physics lol)
 
  • #10
wicked said:
turned to potential energy?
(remeber i suck at physics lol)

During the process of deceleration (from the bottom of the ramp to point D) the potential energy of the block stays the same.

But keep the potential energy in mind for part b). :wink:
 
  • #11
ًًًٍُُW = PE2 - PE1 = mgh2 - mgh1

i need h , i got m and g ofcorse , still confused bout getting W
 
  • #12
The good thing about potential energy in this problem: you can choose any height as zero-level for it.

I'd suggest setting [tex]h_1=0\,m[/tex] in your equation so that [tex]h_2=h[/tex] in the sketch.

"Energy conservation" is the key in b)

Right at the moment the block separates from the spring it has a certain velocity [itex]v_1[/itex] and is situated at the height [tex]h[/tex]. What does that mean for the total Energy (kinetic+potential)? At the bottom of the slope (point B) the total energy is conserved. The block "gained" kinetic energy but "lost" potential energy. It's better to speak of conversion of energy here and in general.

Edit: The forum is quite slow for me today. Sorry if I can't give you an instant reply. :smile:
 
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  • #13
aa for f u c k's sake can u just post the solution , i need this S#!t for 2moro i can't be discussin one Q the whole night ,gotta do 16 Q
 
  • #14
wicked said:
aa for f__k's sake can u just post the solution , i need this S#!t for 2moro i can't be discussin one Q the whole night ,gotta do 16 Q

:rolleyes: Challenges are meant to test us. It's up to you if you want to learn something from it or take the easy route and avoid them at all costs.

Also: I'm sure if you'd be able to solve this specific question, the other ones will appear a whole lot easier in your eyes as they seem to deal with exactly the same basics: Newton's laws and energy conversion.
 
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  • #15
fine fine ill do it my self , thanks anyway

peace ,im out
 
  • #16
eazy route , coz this whole physics corse won't do me any good for the rest of my life,i wana be a goddam dentist
 
  • #17
yea ,ill try ..if not fu-ck it ill try to do better on my final
peace out
 
  • #18
wicked said:
i wana be a goddam dentist

And I honestly wish you the best of luck in becoming a good dentist. Physics might not be "your thing", but please stay open minded to any topics/subjects that might cross your path. It's a good approach for life in general and you don't want to miss the fun parts of it, right? :smile:

Regards,

nazzard
 
  • #19
kol 5ara

thanx i will :)
 

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