Kinematics 2D: Horizontal Velocity of Spiked Volleyball

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SUMMARY

The horizontal component of a volleyball's velocity when spiked at an initial velocity of 15 m/s and an angle of 55 degrees below the horizontal is calculated using the formula for horizontal velocity. The calculation yields a horizontal velocity of 8.6 m/s, derived from the equation: horizontal velocity = velocity * cos(angle). This confirms that the approach and calculation are correct, providing a definitive answer to the problem presented.

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Homework Statement


A volleyball is spiked so that it has an initial velocity of 15m/s directed downward at an angle of 55degrees below the horizontal. What is the horizontal component of the ball's velocity when the opposing player fields the ball?

Homework Equations


horizontal velocity = velocity * cos(angle)


The Attempt at a Solution


15m/s * cos(55) = 8.6m/s
It seems like I'm missing something.
 
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Looks good to me.
 
Really? I spent a long time on this thinking it was too easy to be correct...haha.
Thank you!
 

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