- #1

agargento

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## Homework Statement

A regulation volleyball court is L = 18.0 m long and a regulation volleyball net is

*d*= 2.43 m high. A volleyball player strikes the ball a height

*h*= 1.98 m directly above the back line, and the ball's initial velocity makes an angle θ = 39° with respect to the ground (see the figure). At what initial speed must the ball be hit so that it just barely makes it over the net? (Assume the volleyball is hit so that its path is parallel to the side-line as seen from an observer directly above the court, and that the volleyball is a point object.)

## Homework Equations

V=V

_{0}+at

r(t)=r

_{0}+v

_{0}t+½at

^{2}

## The Attempt at a Solution

Well, there are six parts to this question. I did four of them.

(a. is in the question)

b. What is the maximum height above the court reached by the ball in this case?

c.At what initial speed must the ball be hit so that it lands directly on the opponent's back line?

d.What is the maximum height reached by the ball in this case?

Here are my answers:

a. 9.81 m/s

b. 3.92 m

c. 12.6 m/s

d. 5.19 m

I'm stuck at e. and f.

f. In volleyball, it is often advantageous to serve the ball as hard as possible. If you want the ball to land in the opponent's court, however, there is an upper limit on the initial ball speed for a given contact point. At this maximum speed, the ball just barely makes it over the net and then just barely lands in bounds on the back line of the opponent's court. For the contact point given in the previous problems, what is this maximum initial speed?

e. If you hit the ball at this maximum speed, at what angle should you strike it in order to make sure the ball lands in bounds?

--------------------

I don't even know where to start. First ,according to c. can the ball have an even higher speed? won't it get out of the field? If not, so how do I find the maxium speed it can have? I don't get how is this different then c.

e. Well... first we must find f ;)

Would love some help. Really stumped.