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the question is:

A 62 kg person in an elevator is moving up at a constant

speed of 4.0 m/s for 5.0 s. T / I C

(b) Calculate the work done by the normal force on the person.

(c) Calculate the work done by the force of gravity on the

person.

(d) How would your answers change if the elevator were

moving down at 4.0 m/s for 5.0 s?

2. Homework Equations

W= F x Δd

and i think

Δd= (vf + vi/2)Δt

fg=m.g

3. The Attempt at a Solution

for b) i did Δd= (vf + vi/2)Δt and got displacement which is 10 m and then i did fn=fg since fnet is 0 which means that they have the same force. and for that i got 607.6 N

p.s the answer in the back is 12 kJ which i dont get?