Kinematics - calculating acceleration

In summary, Jack is driving at a steady speed of 25 m/s when he passes Jill who is parked. Jill then starts accelerating at a rate of 4.0 x 10-3 m/s2 in the same direction. To find out how long it takes for Jill to catch up to Jack, we can use the equations x(t)=25t and x(t)=(1/2)(4.0E-3)t2. After solving for the same position, we get a time of 12500 seconds or 3.47 hours.
  • #1
TheronSimon
37
0

Homework Statement



Jack is driving with a pail of water along a straight pathway at a steady 25 m/s when he passes Jill who is parked in her minivan waiting for him. When Jack is beside Jill, she begins accelerating at the rate of 4.0 x 10-3 m/s2 in the same direction that Jack is driving. How long does it take Jill to catch up to Jack?

Homework Equations





The Attempt at a Solution



I'm superbly and completely stumped by this, I really have no idea how to even begin solving this. If anyone could help that would be most appreciated!
 
Physics news on Phys.org
  • #2
If Jack is driving at a steady 25 m/s, then kinematics tell us that:

x(t)=25t

Now, Jill, initially at rest, starts accelerating at the rate of 4.0E-3 m/s2, which results in:

x(t)=(1/2)(4.0E-3)t2

We are admitting that they both start their movement at the origin of (Oxy). You can now solve it for the same position (same x).
 
  • #3
so 25 = 2x10^-3 (t)^2
25= SQRT0.002
25= 0.0447
t= 25/0.0447
t= 559s
or t = 9.3 minutes
 
  • #4
TheronSimon said:
so 25 = 2x10^-3 (t)^2

25t, not 25. You must solve a quadratic equation.
 
  • #5
you lost me sorry :'(
 
  • #6
Mathoholic! said:
x(t)=25t

Mathoholic! said:
x(t)=(1/2)(4.0E-3)t2

These are the two equations. You forgot take the t term in the first equation into account.
 
  • #7
so how about...
25 t^2 = .002 m/s^2 t^2 divide both sides by t^2
25 = .002 m/s^2 divide both by 0.002^2
so 25/ 0.002
so if we cancel out the m/s we are left with a sec so an answer of time of 12500 seconds or 3.47 hours.
 
  • #8
Nice work, that is correct.
 
  • #9
TheronSimon said:
so how about...
25 t^2 = .002 m/s^2 t^2 divide both sides by t^2
25 = .002 m/s^2 divide both by 0.002^2
so 25/ 0.002
so if we cancel out the m/s we are left with a sec so an answer of time of 12500 seconds or 3.47 hours.

It's partiallly wrong, Jack's speed is constant (thus no acceleration!).

25t=(1/2)(4.0E-3)t2 → (2.0E-3)t2-25t=0

You can either use the quadratic formula or cancel the product like so:

t=0 [itex]\vee[/itex] t=25/(2.0E-3)=12500s

You got the solution right but you used a wrong method as 25≠0.002.
 
  • #10
Wow whoops, totally didn't see that xD
 

FAQ: Kinematics - calculating acceleration

What is kinematics?

Kinematics is the branch of physics that studies the motion of objects without considering the forces involved.

What is acceleration?

Acceleration is the rate at which an object's velocity changes over time. It is a vector quantity and is measured in meters per second squared (m/s^2).

How do you calculate acceleration?

Acceleration can be calculated by dividing the change in velocity by the change in time. The formula for average acceleration is a = (vf - vi) / t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

What is the difference between average and instantaneous acceleration?

Average acceleration is the overall change in velocity over a period of time, while instantaneous acceleration is the acceleration at a specific moment in time. Average acceleration is calculated using the change in velocity over a longer time interval, while instantaneous acceleration is calculated using the change in velocity over an infinitely small time interval.

How does acceleration relate to other kinematic quantities?

Acceleration is related to other kinematic quantities such as displacement, velocity, and time through various equations. For example, the relationship between velocity and acceleration is given by the equation vf = vi + at, where vf is final velocity, vi is initial velocity, a is acceleration, and t is time.

Back
Top