- #1

Civil_Disobedient

- 15

- 0

## Homework Statement

A person runs at a constant speed of 4.0 m/s to catch a stationary bus. When she is 6.0m behind it (t=0s), the bus leaves, accelerating with a (constant) acceleration of 1.2 m/s^2. How long does it take her to catch up to the bus?

## Homework Equations

X = Xo + Vot + 0.5at^2

## The Attempt at a Solution

Variables for the person:

Vo = 4

Xo = -6

Variables for the bus:

Vo = 0

Xo = 0

a = 1.2

Equation for the person:

X = Xo + Vot

**X = -6+4t**

Equation for the bus:

X = 0.5at^2

X = 0.5(1.2)t^2

**X = 0.6t^2**

Setting the two equations equal to each other, I got:

-6 + 4t = 0.6t

-3.4t = -6

**t = 5.67s**

Not sure what to do from here or if I even did everything correctly up to this point. Thanks for your help.