Kinematics Equations and a Cliff

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A car drives off a 100m cliff and must land 90m into a body of water, 30m away horizontally. The discussion focuses on using kinematics equations to determine the required horizontal velocity for the car to achieve this. Key points include the independence of vertical and horizontal motions, with the vertical motion being free fall and the horizontal motion having constant velocity. The correct approach involves calculating the time to fall using Δy = 1/2gt² and then applying that time to find the horizontal distance using Δx = v₀t. The final calculated horizontal velocity needed is debated, with one participant suggesting a value of 23.9 m/s as the correct answer.
  • #31
MarchON said:
Haha, not worth it. And I have no idea why he made the solution so overly confusing.
Coward! A brave man should fight for the truth!
You can ask him to explain the "correct" solution to you as you got different result... And then he either founds his own error or we find his error or our error, if any.
If he made the solution confusing, he could have confused himself.
 
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  • #32
I really like the two headings for horizontal and vertical parts of the motion in that example. That is a great first step in any two dimensional motion problem. The second step is to identify which part is accelerated motion and write the appropriate formulas.
 

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