- #1
Rasiel
- 8
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Member advised to use the homework template and show their own efforts.
Could someone please assist me in deriving the following projectile motion equations from the following kinematics equations?
Kinematics Equations:
Δx = v0xt + ½at2 ; Δy = v0yt + ½at2
vx = v0x + at ; vy = v0y + at
Δx = ½(v0x + vx)t ; Δy = ½(v0y + vy)t
vx2 = v0x2 + 2aΔx ; vy2 = v0y2 + 2aΔy
Projectile Motion Equations:
Flight Time = [ 2v0sin(θ) ] / g
Max Height = [ v02sin2(θ) ] / 2g
Horizontal Range = [ v02sin(2θ) ] / g
Time to Reach Top = √((2 * MAX HEIGHT) / g)
Kinematics Equations:
Δx = v0xt + ½at2 ; Δy = v0yt + ½at2
vx = v0x + at ; vy = v0y + at
Δx = ½(v0x + vx)t ; Δy = ½(v0y + vy)t
vx2 = v0x2 + 2aΔx ; vy2 = v0y2 + 2aΔy
Projectile Motion Equations:
Flight Time = [ 2v0sin(θ) ] / g
Max Height = [ v02sin2(θ) ] / 2g
Horizontal Range = [ v02sin(2θ) ] / g
Time to Reach Top = √((2 * MAX HEIGHT) / g)