Kinematics: Find Displacement in 2x Time w/ Constant Acceleration

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SUMMARY

The discussion focuses on calculating the displacement of a particle under constant acceleration when given its initial velocity and final velocity after a certain time. The key kinematic equation used is \( s = ut + \frac{1}{2}at^2 \), where \( s \) is displacement, \( u \) is initial velocity, \( a \) is acceleration, and \( t \) is time. The challenge presented is to express displacement in terms of initial velocity, final velocity, and acceleration for double the time interval. The solution requires algebraic manipulation to derive the expression accurately.

PREREQUISITES
  • Understanding of kinematic equations, specifically \( s = ut + \frac{1}{2}at^2 \)
  • Knowledge of the relationship between initial velocity, final velocity, and acceleration
  • Basic algebra skills for manipulating equations
  • Familiarity with concepts of constant acceleration in physics
NEXT STEPS
  • Study the derivation of kinematic equations in detail
  • Learn how to manipulate algebraic expressions involving variables
  • Explore examples of displacement calculations under constant acceleration
  • Investigate the implications of varying initial velocities on displacement outcomes
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Students studying physics, particularly those focusing on kinematics, as well as educators seeking to clarify concepts related to displacement and acceleration in motion problems.

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Homework Statement


A particle has initial velocity and constant acceleration. If its velocity after certain time is v then what will its displacement be in twice of that time?



Homework Equations





The Attempt at a Solution



Im thinking about using one of the classic kinematics equations, however i don't have the value of the initial velocity. So I am stuck in this problem. If someone could explain to me how i find this velocity, i would be grateful.
 
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You're expected to find a solution as an algebraic expression in terms of the mentioned initial velocity, final velocity, and acceleration.
 

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