- #1
pstfleur
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1. In getting ready to slamdunk the ball, a basketball player starts from rest and sprints to a speed of 6.0m/s in 1.5seconds. Assuming that the player accelerates uniformly, determine the distance he runs
2. Vf=Vo+at, VF^2=Vo^2+2a(Delta x)
3. Vf= 0m/s+(6.0)(1.5)= 9
Delta X= Vf^2-V0^2/2a= 81-0/12=6.75
Delta X should be the distance he's running. The book answer is giving me 4.5m, but I am coming up with 6.75..Am I plugging in wrong values?
2. Vf=Vo+at, VF^2=Vo^2+2a(Delta x)
3. Vf= 0m/s+(6.0)(1.5)= 9
Delta X= Vf^2-V0^2/2a= 81-0/12=6.75
Delta X should be the distance he's running. The book answer is giving me 4.5m, but I am coming up with 6.75..Am I plugging in wrong values?