Auburn2017
- 59
- 1
This is just not making sense to me.TSny said:Speed doesn't have a direction.
The discussion revolves around the kinematics of a rigid body, specifically a wheel rotating about a fixed axis. The problem involves determining the absolute acceleration of point C on the wheel, given the velocities of points A and B, and the radius of the wheel.
The discussion is ongoing, with participants providing insights and questioning each other's reasoning. Some guidance has been offered regarding the relationships between the points' velocities and accelerations, and there is a focus on ensuring clarity in vector representation.
Participants are working within the constraints of the problem as stated, referencing specific equations related to rigid body motion. There is an emphasis on understanding the components of acceleration and the geometry involved in the setup.
This is just not making sense to me.TSny said:Speed doesn't have a direction.
but you can't get acceleration from speedTSny said:Speed is the magnitude of the velocity. Velocity is a vector. Speed is a scalar.
So, the velocity of C is not the same as the velocity of A. But the speed of C does equal the speed of A.
how would you find the angular acceleration and velocity of the wheel?TSny said:You can get the magnitude of the normal acceleration from the speed and the radius. Normal acceleration is also called centripetal acceleration.
rA=rB+rA/B
vA=vB+vA/B
aA=aB+aA/B
vA/B=ω×rA/B
aA/B=(aA/B)n+(aA/B)t
(aA/B)n=ω×(ω×rA/B)
(aA/B)t=α×rA/B
Yes I am familiar with such equationTSny said:Are you familiar with the formula acentripetal = v2/r ?
Or are you required to solve this problem using only the equations that you listed:
49/6TSny said:Great! What do you get for the magnitude of the centripetal acceleration?
Why the square root?√(49)/6
brain fart just 49/6TSny said:Why the square root?
the magnitude of the normal acceleration would be radius times angular acceleration which we know from point B correct?TSny said:OK. All you need to do is put it all together now.
But what is the value of anTSny said:Yes, but why go there? You already have values for an and at. Use these in your earlier expressions to obtain the normal and tangential acceleration vectors in terms of i and j. For example, see your post #21.
SAMETSny said:How does the magnitude of the tangential acceleration of C compare to the magnitude of the tangential acceleration of B?
When I plug and chug I do not get the answer :/TSny said:Yes.