Auburn2017
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This is just not making sense to me.TSny said:Speed doesn't have a direction.
The discussion focuses on the kinematics of rigid body plane motion, specifically analyzing the absolute acceleration of Point C on a rotating wheel with a radius of 6 inches. The velocities of Points A and B are given as -7j in/sec and -4i in/sec², respectively. The participants conclude that the absolute speed of Point C equals that of Point A, while the tangential acceleration of Point C is expressed in terms of unit vectors, with the normal acceleration directed towards the center of the circle. The discussion emphasizes the importance of understanding both tangential and normal components of acceleration in rigid body motion.
PREREQUISITESStudents and professionals in mechanical engineering, physics, and applied mathematics who are studying the dynamics of rigid bodies and analyzing rotational motion.
This is just not making sense to me.TSny said:Speed doesn't have a direction.
but you can't get acceleration from speedTSny said:Speed is the magnitude of the velocity. Velocity is a vector. Speed is a scalar.
So, the velocity of C is not the same as the velocity of A. But the speed of C does equal the speed of A.
how would you find the angular acceleration and velocity of the wheel?TSny said:You can get the magnitude of the normal acceleration from the speed and the radius. Normal acceleration is also called centripetal acceleration.
rA=rB+rA/B
vA=vB+vA/B
aA=aB+aA/B
vA/B=ω×rA/B
aA/B=(aA/B)n+(aA/B)t
(aA/B)n=ω×(ω×rA/B)
(aA/B)t=α×rA/B
Yes I am familiar with such equationTSny said:Are you familiar with the formula acentripetal = v2/r ?
Or are you required to solve this problem using only the equations that you listed:
49/6TSny said:Great! What do you get for the magnitude of the centripetal acceleration?
Why the square root?√(49)/6
brain fart just 49/6TSny said:Why the square root?
the magnitude of the normal acceleration would be radius times angular acceleration which we know from point B correct?TSny said:OK. All you need to do is put it all together now.
But what is the value of anTSny said:Yes, but why go there? You already have values for an and at. Use these in your earlier expressions to obtain the normal and tangential acceleration vectors in terms of i and j. For example, see your post #21.
SAMETSny said:How does the magnitude of the tangential acceleration of C compare to the magnitude of the tangential acceleration of B?
When I plug and chug I do not get the answer :/TSny said:Yes.