Kinematics - Packing falling from plane to ship type problem.

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btbam91
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[PLAIN]http://img600.imageshack.us/img600/1236/kinema.jpg Focusing on the plane first:

When the package is let go, it has a Vy of V, no acceleration, so y=Vy*t

In the z direction:

a=-g
Vz=-gt
z=.5H-.5gt^2

In the x direction:

x=0

Now for the ship:

Given is Vs=Vx=U-at
x=(1/20)*H+Ut-.5at^2y=H

z=0Did I set these up correctly?

Where do I go from here?

The answer is V=10U

Thanks!
 
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Okay, finally I got the correct answer. I'll give hints.

Hint 1: don't think in terms of vectors, think in terms of distance versus time.
Hint 2: get an equation in H,U and a.