Kinematics problem: x(t) --> v(t) --> a(t)

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Homework Help Overview

The discussion revolves around a kinematics problem involving the motion of an object along the x-axis, described by the position function x(t) = −t³ + 6t − 12 m. Participants are tasked with finding the object's velocity and acceleration, as well as determining when it stops.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the appropriate methods for deriving velocity and acceleration from the position function, with some expressing confusion about the relevance of certain equations. Questions arise regarding the necessity of calculus for solving the problem, and participants reflect on their prior experiences with similar problems.

Discussion Status

The conversation is ongoing, with participants offering hints and questioning assumptions about the problem's requirements. Some express uncertainty about their ability to solve the problem without calculus, while others encourage exploration of the relationships between position, velocity, and acceleration.

Contextual Notes

There is a noted lack of calculus knowledge among some participants, which raises concerns about their ability to tackle the problem effectively. The original poster indicates that previous problems did not involve calculus, highlighting a shift in difficulty.

ilanmichaeli
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1. Problem statement:
an object moves along the x-axis so it's position at any given moment is
x(t) = −t3(to the third power) + 6t − 12 m.
a. what is it's velocity at any given moment
b. what is it's acceleration
c. at what moment does the object stops

Homework Equations


s=vt+1/2at2

The Attempt at a Solution


due to the weird expersion they gave i couldn't even think about any reasonable thing to do, but i tried nonetheless to solve for it but in vein... i'll be grateful for some assistance
 
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ilanmichaeli said:
s=vt+1/2at2
That equation applies to motion with constant acceleration. Not to this problem.

Hint: Calculus.
 
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ilanmichaeli said:
1. Problem statement:
an object moves along the x-axis so it's position at any given moment is
x(t) = −t3(to the third power) + 6t − 12 m.
a. what is it's velocity at any given moment
b. what is it's acceleration
c. at what moment does the object stops

Homework Equations


s=vt+1/2at2

The Attempt at a Solution


due to the weird expersion they gave i couldn't even think about any reasonable thing to do, but i tried nonetheless to solve for it but in vein... i'll be grateful for some assistance

That's not the correct Relevant Equation. You are given position as a function of time x(t), and are asked to find the velocity v(t) and acceleration a(t). What operation do you use to get v(t) from x(t)? And what operation do you use to get a(t) from v(t)?

Also, I'll add some descriptive words to your thread title. "kinematics problem" is not very descriptive of this problem...

EDIT -- Beaten to the punch by Doc Al again! :smile:
 
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berkeman said:
That's not the correct Relevant Equation. You are given position as a function of time x(t), and are asked to find the velocity v(t) and acceleration a(t). What operation do you use to get v(t) from x(t)? And what operation do you use to get a(t) from v(t)?

Also, I'll add some descriptive words to your thread title. "kinematics problem" is not very descriptive of this problem...

EDIT -- Beaten to the punch by Doc Al again! :smile:
thanks for your help and regarding to what you've said i would use v=s/t for velocity and a=v/t for acceleration. in fact i did try to divide that expression by time (using v=s/t) but it just didn't work out for me unless I'm doing it wrong.. :(.
 
ilanmichaeli said:
i would use v=s/t for velocity and a=v/t for acceleration.
Those only work for constant velocity and constant acceleration, respectively.

How about using the hint I gave?
 
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Doc Al said:
Those only work for constant velocity and constant acceleration, respectively.

How about using the hint I gave?
if i still don't know any calculus i don't have any hope for solving this problem? because that's the case unfurtunately
 
ilanmichaeli said:
if i still don't know any calculus i don't have any hope for solving this problem? because that's the case unfurtunately
Oh well. How did you get this problem if you haven't had calculus?
 
ilanmichaeli said:
if i still don't know any calculus i don't have any hope for solving this problem? because that's the case unfurtunately

It sure looks like a Calculus problem to us. What class is this from?

EDIT -- Dang it, dang it, dang it! :wink:
 
Doc Al said:
Oh well. How did you get this problem if you haven't had calculus?
it's from a collection of problems of kinematics, up to this question i could solve everything they asked because there wasn't any calculus involved, but from this one and on every thing looks kinda messy :)
 
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berkeman said:
EDIT -- Dang it, dang it, dang it! :wink:
LOL! :cool:
 
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ilanmichaeli said:
it's from a collection of problems of kinematics, up to this question i could solve everything they asked because there wasn't any calculus involved, but from this one and on every thing looks kinda messy :)
Yeah, I suspect the problems went from the basics up to the more advanced. Time to learn some calc!
 
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Doc Al said:
LOL! :cool:
thanks anyway for your time. both of you.
 
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  • #13
ilanmichaeli said:
1. Problem statement:
an object moves along the x-axis so it's position at any given moment is
x(t) = −t3(to the third power) + 6t − 12 m.
a. what is it's velocity at any given moment
b. what is it's acceleration
c. at what moment does the object stops

Homework Equations


s=vt+1/2at2

The Attempt at a Solution


due to the weird expersion they gave i couldn't even think about any reasonable thing to do, but i tried nonetheless to solve for it but in vein... i'll be grateful for some assistance
What's weird about the expression showing position as a function of time?

What's the relationship between the change in location, x(t), w.r.t. time and the velocity? What's the relationship between the change in velocity, v(t), w.r.t. time and the acceleration?

You should have learned the definitions of velocity and acceleration by now. The SUVAT equations are special cases where acceleration is a constant.
 
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