1. The problem statement, all variables and given/known data Dave and Andrew are racing. Dave running at a constant speed of 20m/s is passed by Andrew. 2.0s after Andrew passes, Dave accelerates at 1.0m/s^2 until he catches up with Andrew 25s later. What is Andrew's velocity (he does not accelerate)? 2. Relevant equations Kinematics Formulas. 3. The attempt at a solution d=vit+1/2at^2 =(20)(25)+1/2(1)(25)^2 =812.5 Dave travels 812.5m. v=d/t =(812.5)(25+2) =30.7m/s I'm not sure if the way I did it was correct. Can someone please tell me how to do it. If you think I'm right though can you please tell me. Thanks!!