Kinematics question concerning the direction of avg acceleration

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Homework Help Overview

The discussion revolves around a kinematics problem involving the calculation of average acceleration for a car changing its velocity from 25 m/s east to 25 m/s south over a period of 15 seconds. Participants are exploring the direction of the average acceleration and the reasoning behind the discrepancy between their calculations and the textbook answer.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss vector diagrams and the use of the Pythagorean theorem to find resultant velocities. Questions arise regarding the interpretation of directional components and the reasoning behind the calculated direction of average acceleration.

Discussion Status

The discussion is ongoing, with participants questioning the assumptions made in their calculations and exploring different interpretations of the vector components involved. Some guidance has been offered regarding the change in velocity and its direction, but no consensus has been reached.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available for discussion. The focus is on understanding the vector relationships and the implications of direction in the context of average acceleration.

justrandom94
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alright so here's a pretty straight forward question asking to find the avg acceleration:

A car with a velocity of 25m/s [E] changes its velocity to 25 m/s in 15s. Calculate
avg acceleration.

So i drew out the vector diagram, found the resultant velocity and solved for the avg acceleration. My answer was right but the direction was wrong. My answer was 2.4 m/s^2 [45 degrees south of east ]
however, the books answer is 2.4 m/s^2 [45 degrees S of W] Can anyone explain to me
why it is south of WEST and not East?
 
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if the acceleration was all going south and east then the velocity would only increase in the south and east directions
after the cars velocity has changed, what happened to the eastward component of velocity?
 
when i drew it out first i drew out the east ward vector then the south one, and the resultant vector connecting the two allows me to use Pythagorean therom so no components were needed to find the resultant velocity, the east velocity and south velocity are at right angles to one another
 
justrandom94 said:
alright so here's a pretty straight forward question asking to find the avg acceleration:

A car with a velocity of 25m/s [E] changes its velocity to 25 m/s in 15s. Calculate
avg acceleration.

So i drew out the vector diagram, found the resultant velocity and solved for the avg acceleration. My answer was right but the direction was wrong. My answer was 2.4 m/s^2 [45 degrees south of east ]
however, the book's answer is 2.4 m/s^2 [45 degrees S of W] Can anyone explain to me
why it is south of WEST and not East?

You need to find the change in velocity, divided by the elapsed time.

\vec{\Delta v}=\vec{v}_{\text{final}}-\vec{v}_{\text{initial}}

You can also find the change in velocity by asking yourself: what vector must be added to the initial velocity so that the resultant is equal to the final velocity?
\vec{v}_{\text{final}}=\vec{v}_{\text{initial}}+ \vec{\Delta v}​
 
justrandom94 said:
when i drew it out first i drew out the east ward vector then the south one, and the resultant vector connecting the two allows me to use Pythagorean therom so no components were needed to find the resultant velocity, the east velocity and south velocity are at right angles to one another

okay, the vector that points from the initial velocity to the final velcity, it is the one that gives you the change in velocity, what way is that vector facing?
 

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