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"You are on top of a building 186 meters high you throw a ball downard at a speed of 18m/sec"

After calculating time for hitting the ground final velocity and average velocity the next question says:

"Suppose instead that at the same moment that this ball was thrown downward from the roof a second ball was thrown upward from the ground with a speed of 32m/s"

I know that when theres simultaneous motion you are supposed to find what the two objects have in common but I can't seem to find it.

I found the time to hit the ground for the first ball was 4.59, its final velocity was -62.98m/s and its average velocity was -40.52m/s.

I figured the time it takes the ball from the ground to reach a velocity of 0 is 3.27seconds and the height it reaches is 52.32 meters I'm not sure what to do now though, somebody please give me a hint or steer me in the right direction. Thank you.

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# Kinematics simultaneous motion problem!

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