1. The problem statement, all variables and given/known data Suppose you adjust your garden hose nozzle for a hard stream of water. You point the nozzle vertically upward at a height of 1.5 above the ground. When you quickly turn off the nozzle, you hear the water striking the ground next to you for another 2.0 . find the water speed as it leaves the hose nozzel 2. Relevant equations v = v_o + at x = x_o + v_o*t + (1/2)at^2 v^2 = v_o^2 + 2a(x - x_o) v_a = (v + v_o)/2 where v_o is initial velocity x_o is initial distance v_a is average velocity 3. The attempt at a solution dunno if I can actually do this but I derived my own equation adding the top half (the parabola area) and the bottom the part equal 1.5m top 0 = 2v_o + 19.6t ( v_o + at) for both 2 halfs of the parabola bottom -1.5 = v_o*t + 4.9t^2 add top and bottom 0 = v_o*t - 4.9t^2 +1.5 + 2v_o + 19.6t simplify -v_o = (-4.9t^2 + 19.6t +1.5)/ (t+2) solve for v_o with t = 2 v_o = 5.275 m/s I dunno if I was mathematically correct to add those equations together, can anyone help please Thank You.