(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Suppose you adjust your garden hose nozzle for a hard stream of water. You point the nozzle vertically upward at a height of 1.5 above the ground. When you quickly turn off the nozzle, you hear the water striking the ground next to you for another 2.0 . find the water speed as it leaves the hose nozzel

2. Relevant equations

v = v_o + at

x = x_o + v_o*t + (1/2)at^2

v^2 = v_o^2 + 2a(x - x_o)

v_a = (v + v_o)/2

where v_o is initial velocity x_o is initial distance v_a is average velocity

3. The attempt at a solution

dunno if I can actually do this but I derived my own equation adding the top half (the parabola area) and the bottom the part equal 1.5m

top

0 = 2v_o + 19.6t ( v_o + at) for both 2 halfs of the parabola

bottom

-1.5 = v_o*t + 4.9t^2

add top and bottom

0 = v_o*t - 4.9t^2 +1.5 + 2v_o + 19.6t

simplify

-v_o = (-4.9t^2 + 19.6t +1.5)/ (t+2)

solve for v_o with t = 2

v_o = 5.275 m/s

I dunno if I was mathematically correct to add those equations together, can anyone help please

Thank You.

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# Homework Help: Kinematics Water shooting out of hose

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