1. The problem statement, all variables and given/known data Suppose you adjust your garden hose nozzle for a hard stream of water. You point the nozzle vertically upward at a height of 1.5m above the ground. When you quickly move the nozzle away from the vertical, you hear the water striking the ground next to you for another 2.0s. What is the water speed as it leaves the nozzle? 2. Relevant equations Δx =Vo t + 1/2 at^2 3. The attempt at a solution Δx =Vo t + 1/2 at^2 -1.5m = (2s) Vo + (1/2) (-9.8 m/s^2) (2s)^2 -1.5m = (2s) Vo - 19.6 m Vo = 9.05 m/s Now the above solution seems to be correct, but I am not sure why t should = 2s. I ended plugging 2 sec. in without really thinking about it, but now I am not able to spatially visualize what is going on with the water. Any help appreciated.