Kinetic and Gravitational Energy Related Questions

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SUMMARY

The discussion focuses on the conversion of kinetic and gravitational potential energy through two specific examples involving a ball and a watermelon. In the first example, a 6.5 kg ball launched at 21 m/s reaches a height of 22.5 meters when all kinetic energy is converted to gravitational potential energy. In the second example, a 5 kg watermelon falls from a height of 43.0 meters, achieving a speed of 29.03 m/s upon impact, assuming complete conversion of gravitational potential energy to kinetic energy. Both calculations are confirmed as accurate.

PREREQUISITES
  • Understanding of kinetic energy (Ek) and gravitational potential energy (Eg)
  • Basic knowledge of physics formulas for energy conversion
  • Familiarity with units of mass (kg), height (m), and speed (m/s)
  • Comprehension of gravitational acceleration (g = 9.8 N/kg)
NEXT STEPS
  • Study the principles of energy conservation in physics
  • Learn how to derive and apply the kinetic energy formula: Ek = 0.5 * m * v^2
  • Explore gravitational potential energy calculations: Eg = m * g * h
  • Investigate real-world applications of energy conversion in mechanics
USEFUL FOR

Students in physics, educators teaching energy concepts, and anyone interested in understanding the principles of energy conversion in mechanical systems.

NeomiXD
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1. A 6.5 kg ball is launched upwards from the ground with a speed of 21 m/s. If all of the ball's kinetic energy is converted to gravitational potential energy, how high will the ball go?

Given:

m = 6.5kg
v = 21m/s
Ek = 1433.25 J
g = 9.8 N/kg [down]

Required:

h =?

Solution:

h = Ek/mg
h = 1433.25 J / (6.5kg)(9.8 N/kg)
h = 22.5m

If all of the ball's kinetic energy is converted to gravitational potential, the ball will go 22.5m high.


2. A 5 kg watermelon is placed on the edge of a balcony 43.0 m high. If all of the gravitational potential energy is converted into kinetic energy after the box is pushed off the balcony, how fast will the watermelon be moving when it hits the ground?

Given:

m = 5 kg
h = 43.0 m
g = 9.8 N/kg [down]
EG = 2107 J

Required:

v =?

Solution:

v = square root 2 EG/ m
v = 2(2107 J)/5 kg
v = 29.03m/s

If all of the gravitational potential energy is converted into kinetic energy after the box is pushed off the balcony, the watermelon would be moving at a speed of 29.03m/s.

So, are my calculations correct?
 
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