# Kinetic and Rotational energy of a sphere

Hi guys so this is my first time posting a question on this amazing forum, i hope i am doing this right since i read that no one will help me if i am missing something. Anyways, i am dealing with a physics problem that it driving me crazy (mainly because my teacher does not explain anything!) Here is the problem.

1. Homework Statement

An 7.50-cm-diameter, 320 g sphere is released from rest at the top of a 1.90-m-long, 20.0 incline. It rolls, without slipping, to the bottom.
b. What fraction of its kinetic energy is rotational?
So the known data is:
mass= 0.0320 kg
delta x= 1.90m
wi = 0
vf = 3.02 m/s
Find ratio between rotational and kinectic energies.

## Homework Equations

Kroll = 1/2 (I* w^2) + 1/2(M)(vf)^2 = Krot + Kcm

## The Attempt at a Solution

ok so from part A of the problem i found the velocity at the bottom of the incline to be 3.02 m/s, then i found the final angular velocity. With that all i thought i had to do was plug the data into the previous equation and get an answer:
Since moment of inertia of a cylinder is 2/5MR^2

Kroll = 1/2 (2/5 ) (0.032kg)(0.0375m)^2 ( 80.5 rad/s)^2 + 1/2 ( 0.032 kg)(3.02 m/s)^2

I am getting 0.204 for the Kroll and for the Krot i am getting 0.06... when i devide 0.06/0.204 i get 0.3 which is not the answer :( i have no idea what am i doing wrong! please help me, this homework was due 2 days ago, i am just doing it to understand the concept no for the points, so i would really appreciate your help, wonderful people, thanks!

SammyS
Staff Emeritus
Homework Helper
Gold Member
The mass is 0.32kg, not 0.032kg, but that shouldn't affect the ratio.

Maybe you have too much round-off error.

ok but am i doing this correctly? i mean, am i supposed to divide Krot by Krolling to get a ratio? or is it the other way (Kroll/krot) ?

I don't get it, no matter how i do it, i am still getting around 0.29... and when round i get 0.3 but it's wrong :/

SammyS
Staff Emeritus
Homework Helper
Gold Member
The fraction of the kinetic energy that is rotational is what you are calling Krot / Kroll .

Why are you rounding to 1 significant figure?

i am rounding to two sig figures :( 0.30, cause i get 0.298

please i really need to understand this, i am not getting the answer.. :/

The question is What fraction of its kinetic energy is rotational?, your answer is the relationship between the rotational and translational kinetic energies.

ok, i dont know what that means then, i thought you had to get the ratio between them,,, if so then i am getting 0.30, which is supposed to be wrong...

SammyS
Staff Emeritus