Kinetic Energy and skateboarder

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Homework Help Overview

The discussion revolves around a physics problem involving a skateboarder using a spring to gain speed to ascend a ramp. The problem touches on concepts of kinetic energy, gravitational potential energy, and spring potential energy.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between kinetic energy and gravitational potential energy, questioning the clarity of the problem's wording. Some express confusion about the distinction between kinetic energy and the energy provided by the spring.

Discussion Status

There is ongoing dialogue about the interpretation of the problem, particularly regarding the terminology used in part A. Some participants suggest that the question should be rephrased for clarity, while others confirm calculations related to energy values. The discussion reflects a lack of consensus on the interpretation of kinetic energy in the context of the problem.

Contextual Notes

Participants note potential ambiguities in the problem's wording, particularly concerning the vertical distance and the assumptions about the skateboarder's motion before reaching the ramp. There is also mention of missing information that could affect the calculations.

raman911
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A50-kg skateboarder design a creative way to gain enough speed to coast up a ramp. By compressing a stiff spring. H e finds that he can go 1.5 m up the ramp?
A) How much kinetic energy does the spring give him?
B) The energy in the spring can be calculated using the expression 1/2kx^2 where k= 1470N/m and is called the spring constant and x is the distance the spring is compressed. How much was the spring compressed in this case?

My Proof

A)
Eg= mgh
Eg=50kg*9.8N/kg*1.5m
Eg=735J
So Eg=Ek
Ek=735J
B)
735J=1/2*1470N/m*x^2
x^2=1470J/1470N/m
x=1m
Is That right or Wrong?
 
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Looks fine to me.
 
Dick said:
Looks fine to me.
r u 100% sure?
 
Assuming 'distance up the ramp' means vertical distance, yes. Why aren't you sure??
 
Dick said:
Assuming 'distance up the ramp' means vertical distance, yes. Why aren't you sure??
i am confuse in B.
 
Confused about what? Spring potential energy=gravity potential energy.
 
Dick said:
Confused about what? Spring potential energy=gravity potential energy.

thaxxxxx u
 
The wording on this problem has me confused also. I guess it's 1.5m vertically up from the compressed position of the spring. So that gives him 735J of gravitational POTENTIAL energy at the top, and the spring compression must be 1 meter, as you and Dick have confirmed. But part A asks about how much KINETIC energy he has. He's got none at the top, none at the start, and some varying amount in between. Are you sure part A asks for Kinetic Energy, or is this a typo??
 
It only makes sense if the kinetic energy referred to is his kinetic energy after using the spring and before ascending the ramp. It could have been written more clearly...
 
  • #10
Dick said:
It only makes sense if the kinetic energy referred to is his kinetic energy after using the spring and before ascending the ramp. It could have been written more clearly...
But I don't think there is enuf info given to solve it, since he will have GPE as well as KE just after using the spring, which is unknown without knowing the slope.
 
  • #11
PhanthomJay said:
But I don't think there is enuf info given to solve it, since he will have GPE as well as KE just after using the spring, which is unknown without knowing the slope.

Not if there is a straight run before hitting the ramp. In any event question A should be rewritten to ask "how much energy did the spring give him". Not "kinetic energy". Then the answer is unambiguous and not subject to nit picking.
 
  • #12
Dick said:
Not if there is a straight run before hitting the ramp. In any event question A should be rewritten to ask "how much energy did the spring give him". Not "kinetic energy". Then the answer is unambiguous and not subject to nit picking.
Yes, I wasn't envisioning the 'straight run' concept.
 
  • #13
here diagram

http://img389.imageshack.us/img389/1103/physicrs1.png
 
Last edited by a moderator:
  • #14
As perfectly envisioned by Dick.
 

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