Kinetic Energy of 10kg Object Dropped from 100m

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SUMMARY

The kinetic energy of a 10 kg object dropped from a height of 100 meters can be calculated using the formula KE = 0.5 * m * v^2. Given that the acceleration due to gravity (g) is 10 m/s², the object reaches a velocity of 40 m/s just before impact. Therefore, the kinetic energy right before it hits the ground is 8000 Joules. This conclusion is based on the principles of gravitational potential energy conversion to kinetic energy during free fall.

PREREQUISITES
  • Understanding of gravitational potential energy
  • Familiarity with the kinetic energy formula (KE = 0.5 * m * v^2)
  • Basic knowledge of physics concepts such as mass and acceleration
  • Ability to perform calculations involving units of energy (Joules)
NEXT STEPS
  • Study the derivation of the kinetic energy formula
  • Learn about the conservation of energy in physics
  • Explore the effects of air resistance on falling objects
  • Investigate real-world applications of kinetic energy calculations
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding energy transformations in motion.

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Homework Statement

A 10 kg object is dropped from 100m above. What is the kinetic energy of the object right before it hits the ground?

(Assume: g= 10 m/s^2)

Homework Equations



(Assume: g= 10 m/s^2)

The Attempt at a Solution



I got 100 right before it hits the ground..
 
Last edited:
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What is your attempt at the solution?
 


sernewto said:

Homework Equations



(Assume: g= 10 m/s^2)

What theory/formula do you think you need to use for this problem?
 

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