Kinetic energy after falling to 100m

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SUMMARY

A 250 g object dropped from a height of 150 m reaches a kinetic energy of 120 J after falling to 100 m. The calculations utilize the kinematic equation V2^2 = V1^2 + 2ad to determine the final velocity (V2) and the kinetic energy formula Ek = 1/2 mv^2. An alternative method involves calculating the change in gravitational potential energy and equating it to the kinetic energy. Both approaches confirm the accuracy of the 120 J result.

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  • Knowledge of gravitational potential energy concepts
  • Basic physics principles regarding motion and energy
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Smartgurl
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Homework Statement


A 250 g object is dropped from a height of 150 m. What is the kinetic energy after falling to 100m

Homework Equations


V2^2 = V1^2 +2ad
Ek = 1/2 mv^2

The Attempt at a Solution


I used the kinematics equation to find my v2 then I used this to find Ek. I got the answer 120J but I'm not sure if I'm doing this right
 
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Smartgurl said:

Homework Statement


A 250 g object is dropped from a height of 150 m. What is the kinetic energy after falling to 100m

Homework Equations


V2^2 = V1^2 +2ad
Ek = 1/2 mv^2

The Attempt at a Solution


I used the kinematics equation to find my v2 then I used this to find Ek. I got the answer 120J but I'm not sure if I'm doing this right
That solution should work, alternatively you could find the change in the gravitational potential energy and equate that change to the kinetic energy.
 

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