Kinetic energy of moving automobile

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Homework Help Overview

The discussion revolves around kinetic energy in the context of moving automobiles, work done by forces in various scenarios, and projectile motion of a baseball. Participants explore the relationships between speed, kinetic energy, and the effects of forces on work in different situations.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between speed and kinetic energy, questioning the reasoning behind the kinetic energy formula. They also explore the concept of work done by forces in different contexts, such as carrying a bag and moving in an elevator or escalator. Additionally, there is inquiry into the effects of launch angles on the speed of a baseball when it strikes the ground.

Discussion Status

Some participants have offered guidance on the kinetic energy question, affirming the reasoning presented. However, there remains a lack of consensus on the work done in the scenarios involving the shopping bag and the elevator, with participants questioning the implications of constant velocity and the angles involved.

Contextual Notes

Participants are navigating through multiple questions within a single thread, which may lead to confusion. There are also references to specific angles and conditions that affect the calculations of work and energy, indicating a need for clarity on these concepts.

St@rbury
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suppose an atomobile has a kinetic energy of 20,000J. If it moves twice as fast, what will be its kinetic energy? three times as fast?

i think that if the velocity is 2 times as fast, then the energy will be 2times^2, and if it is 3 times as fast, then it will be 3times^2...is that correct? and what is the physics reasoning behind it because i just saw it logically
 
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also, another question

a shopping bag is hangg straight down from your hand as your walk across a horizontal floor. does the force that your hand exerts on the bag's handle do any work> does this force do any wokr while you are ruding up and elevator? does this force do any work while you are rding up and escalator? (assume in all three cases that the velocity is constant)

in the first part of it,the force is upwards, and displacement is to the side, so there is a 90 degree angle and work is done: w=FScos(theata) in the second part, force is up and so is displacement, so there is no work done b/c cos(theata)=0 in that part. and in the last part, there is some angle, so work is being done. However, it said that velocity was constant, and constant velocity=0 acceleration and acording to F=ma, there would b no force...so which is it?
 
and another question,

During batting practice, a baseball player hits a baseball three different times. He makes contact with the ball at the same height and the ball leaves the bat with the
same speed each time. The only difference is the angle with which the ball leaves the
bat. He first hits the ball up at an angle of 30° above the horizontal, then horizontally,
then down at a 30° angle below the horizontal. Which baseball strikes the
ground with the fastest speed? Which strikes the ground with the slowest speed?
(Air resistance is assumed negligible.)

i think that the ball hit below the horizontal would hit the ground with the greatest speed. velocity is distance over time, and the ball hit above the horizontal would have the greatest distance, and so on. however, based on the conservation of energy formula, since all of the initial info is the same, then shouldn't the final velocity b the same for all o them?
 
St@rbury said:
suppose an atomobile has a kinetic energy of 20,000J. If it moves twice as fast, what will be its kinetic energy? three times as fast?

i think that if the velocity is 2 times as fast, then the energy will be 2times^2, and if it is 3 times as fast, then it will be 3times^2...is that correct? and what is the physics reasoning behind it because i just saw it logically

Keep in mind the equation for kinetic energy: K=1/2mv^2
 
yes i know that, so is my reasoning correct?
 
St@rbury said:
yes i know that, so is my reasoning correct?

Your reasoning is correct. I wasn't understanding you at first.
 
ok nice...what about the other problems?
 
St@rbury said:
ok nice...what about the other problems?

In the future, please post separate questions under separate topics. Otherwise, the responses are going to read like the litany of saints.

For question 2, you've got your cos thetas mixed; cos theta is 1 and cos 90 is 0. Regarding net work at constant velocity, yes, it is zero, but does this mean the work done by your hand is 0?
 

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