Kinetic energy of two protons to create a meson?

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SUMMARY

The discussion focuses on calculating the minimum kinetic energy required for two protons to create a π2 meson during their collision. The relevant equation used is E=mc², where the mass of the π2 meson is 135 MeV. The final calculation confirms that the kinetic energy needed for each proton is approximately 2.16 x 10^-11 Joules, which is equivalent to 135 MeV when expressed in the correct units.

PREREQUISITES
  • Understanding of Einstein's mass-energy equivalence (E=mc²)
  • Basic knowledge of particle physics, specifically meson production
  • Familiarity with energy units, including MeV and Joules
  • Concept of momentum conservation in particle collisions
NEXT STEPS
  • Study the process of particle-antiparticle annihilation and meson production
  • Learn about the conservation of energy and momentum in high-energy physics
  • Explore the properties and types of mesons, focusing on the π meson family
  • Investigate experimental setups for proton collisions, such as those in particle accelerators
USEFUL FOR

Students in physics, particularly those studying particle physics, as well as educators and researchers interested in high-energy collisions and meson production processes.

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Homework Statement


This one stumped me a little
Two protons are heading toward each other with equal speeds.
What minimum kinetic energy must each have if a ∏2 meson is to be created in the process?

Homework Equations


E=mc2
p+p→p+p+∏2
E=Ek-mc2 ? not sure if I got this right or even useful

The Attempt at a Solution



E=mc2
=135MeV
=135x106x1.6x10-19
=2.16x10-11
 
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actually I worked it out, it was correct, they just wanted it in MeV
 

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