Kinetic energy of two protons to create a meson?

[R0CC0]

Homework Statement

This one stumped me a little
Two protons are heading toward each other with equal speeds.
What minimum kinetic energy must each have if a ∏² meson is to be created in the process?

Homework Equations

E=mc²
p+p→p+p+∏²
E=E_k-mc² ? not sure if I got this right or even useful

The Attempt at a Solution

E=mc²
=135MeV
=135x10⁶x1.6x10^-19
=2.16x10^-11

 

[R0CC0]

actually I worked it out, it was correct, they just wanted it in MeV