Kinetic Energy of uranium particles

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SUMMARY

The discussion focuses on calculating the kinetic energy of particles resulting from the decay of a uranium-238 atom into a thorium-234 atom and an alpha particle (α-4). The kinetic energy formula K = 1/2mv² is applied, with the thorium atom's velocity given as -2.1 × 10^5 m/s. Participants emphasize the need to compute the kinetic energy of both the thorium and alpha particles, highlighting the importance of momentum conservation to determine the alpha particle's velocity and energy contribution.

PREREQUISITES
  • Understanding of kinetic energy calculations using K = 1/2mv²
  • Knowledge of atomic mass units (amu) and their conversion to kilograms
  • Familiarity with momentum conservation principles in particle physics
  • Basic knowledge of nuclear decay processes, specifically uranium-238 decay
NEXT STEPS
  • Research the mass of the alpha particle (α-4) and thorium-234 for accurate calculations
  • Learn about momentum conservation in nuclear reactions and its applications
  • Explore advanced kinetic energy calculations involving multiple particles
  • Study the principles of nuclear decay and energy release in fission processes
USEFUL FOR

Students studying nuclear physics, educators teaching atomic decay processes, and anyone interested in the energy dynamics of particle interactions in nuclear reactions.

Manh
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Homework Statement


A uranium-238 atom can break up into athorium-234 atom and a particle called an alpha particle, α-4. The numbers indicate the inertias of the atoms and the alpha particle in atomic mass units (1 amu = 1.66 × 10^−27 kg). When an uranium atom initially at rest breaks up, the thorium atom is observed to recoil with an x component of velocity of -2.1 × 10^5 m/s.

Homework Equations


K = 1/2mv^2

The Attempt at a Solution


K = 1/2(1.66 x 10^27 kg)(-2.1 x 10^5 m/s)^2
K = 3.66 X 10^-17 J
 
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There seems to be something missing from your problem statement. What are you meant to be calculating? You seem to have left the question out of the problem statement.
 
DEvens said:
There seems to be something missing from your problem statement. What are you meant to be calculating? You seem to have left the question out of the problem statement.
How much of the uranium atom's internal energy is released in the breakup?
Express your answer to three significant digits and include the appropriate units.
 
You cannot just compute the kinetic energy of the daughter nucleus (which, by the way, is significantly heavier than 1 u). Most of the energy will be carried by the alpha particle.
 
Orodruin said:
You cannot just compute the kinetic energy of the daughter nucleus (which, by the way, is significantly heavier than 1 u). Most of the energy will be carried by the alpha particle.
So, what am I supposed to do since I only know the formula of kinetic energy?
 
You are supposed to compute the total kinetic energy of both particles.
 
Orodruin said:
You are supposed to compute the total kinetic energy of both particles.
Can you guide me how to do that? I know that the total mass of the atom and particle is 1.66 × 10^−27 kg and velocity of the atom is -2.1 × 10^5 m/s. These given values may be plugged into an equation, right?
 
As I already told you, that is not the mass of the particle. It is one atomic mass unit. You know the masses of all particles, if you reread the problem statement you should be able to figure out what they are.

You need to compute the velocity of the alpha particle to know its energy. How can you relate it to what you know?
 
Manh said:
Can you guide me how to do that? I know that the total mass of the atom and particle is 1.66 × 10^−27 kg and velocity of the atom is -2.1 × 10^5 m/s. These given values may be plugged into an equation, right?

You need to look at the mass of the alpha particle. The problem statement tells you it is ##\alpha##-4. This is two protons and two neutrons. But look up the exact mass. Also look up the mass of a Thorium-234.

To get the energy of the Thorium nucleus, you need to conserve momentum. The alpha goes whizzing away in that direction. The Thorium goes the opposite direction. But the Uranium that started all this started at rest. So you conserve momentum. That tells you how fast the Thorium goes. Then you work out its kinetic energy.
 

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