Kinetic Energy Related to Potential

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Object dropped from rest at h0meters. At what height, h1, will K=2U? g=9.8m/s2


K=2U
ET=K-U



(.5)mv2=2(mgh)
v2=gh
(v2)/g=h


Thanks. :)
 

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  • #2
Andrew Mason
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Object dropped from rest at h0meters. At what height, h1, will K=2U? g=9.8m/s2


K=2U
ET=K-U



(.5)mv2=2(mgh)
v2=gh
(v2)/g=h


Thanks. :)
Your question does not make sense. Please give us the entire question exactly as you were given it.

AM
 
  • #3
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Before dropping the object the total energy is E = K + U = 0+mgh.

After falling, the total energy will be E' = K' + U' = 2U' + U' = 3U'

As we know, E = E'

Then, mgh = 3mgh' --> h' = 1/3 h
 
  • #4
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AM- Sorry I wasn't clear enough for you, but thanks for looking it over,

M- That's just what I needed. :)
 

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