Kinetic Energy - Spring Stiffness

[Kev1n]

1. A container of mass 100kg runs on overhead rails. the container is mounted on two wheels each having a mass of 15 kg,a diameter of 1.2 m and a radius of gyration of 0.4 m.
A)the total kinetic energy of the vehicle when traveling at 4ms-1
B) the spring stiffness reguired to bring the vehicle to rest in a distance of 300mm.



2. KE=(1/2)MV^2, Spring KE = (1/2) x stiffness x displacement ^2



3. A). KE = (1/2) 115x4^2 = 920nm
B). unsure

any pointers appreciated

 

[rl.bhat]

Total energy = Energy due to transactional motion of container + two wheels, and energy due to rotational motion of wheels.