Kinetic energy with momentum equation

~christina~
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[SOLVED] kinetic energy with momentum equation

Homework Statement



A particle of mass m moves with momentum of magnitude p. Show that the kinetic E of particle is given by [tex]K= p^2/2m[/tex]

express magnitude of particle's momentum interms of it's Kinetic Energy and mass.


Homework Equations



Kf + Uf= Ki + Ui

1/2mvf + mgy = 1/2mvi + mgy

pf= pi

mvf= mvi

The Attempt at a Solution



not exactly sur how to incorperate the momentum into the kinetic E equation.

my attempt looks ridiculous.

not sure if it's Kf= Ki
because they just say the Kinetic E

K= 1/2mv^2

p= mv

[tex]K= \frac{P*v} {2}[/tex]

What am I doing incorrectly?


b) Express magnitude of the particle's momentum in terms of it's kinetic E and mass

I guess I would just rearrange the equation they gave me

[tex]K= \frac{p^2} {2m}[/tex]

[tex]p= \rad{K*2m}[/tex]
 
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This would be correct if K = p/2m

But you have to isolate p^2. Dont you miss the [tex]{\sqrt {equation}}[/tex] ?
 
~christina~ said:
not exactly sur how to incorperate the momentum into the kinetic E equation.

my attempt looks ridiculous.

not sure if it's Kf= Ki
because they just say the Kinetic E

K= 1/2mv^2

p= mv

[tex]K= \frac{P*v} {2}[/tex]

What am I doing incorrectly?
Nothing incorrect, just incomplete. Multiply the expression on the right by m/m.

b) Express magnitude of the particle's momentum in terms of it's kinetic E and mass

I guess I would just rearrange the equation they gave me

[tex]K= \frac{p^2} {2m}[/tex]

[tex]p= \rad{K*2m}[/tex]

That looks good.
 
becuse:[tex]P^{2}=m^{2}v^{2}[/tex]
so:[tex]k=1/2\cdot\frac{P^{2}}{m}[/tex]

You lose one stage:[tex]v=\frac{p}{m}[/tex]

This equation is important.Because in the Hamitonian equation,all the element must be
expressed by P and q.q is the generalized coordinate .
 
Last edited:
Thank you everyone. I get why I have to multiply it by m/m.
 

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