Kinetic Fictional Force help please

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SUMMARY

The discussion centers on calculating the required force P to ensure that the net work done by the applied force and the kinetic frictional force on a 109-kg crate is zero. Given that the coefficient of kinetic friction is 0.260 and the angle of force application is 38.3° below the horizontal, the relationship between the normal force and the frictional force must be established. The work done by force P must equal the work done against kinetic friction to achieve a net work of zero.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of kinetic friction and its coefficient
  • Ability to calculate work done by forces
  • Familiarity with vector components of forces
NEXT STEPS
  • Calculate the normal force acting on the crate using the equation N = mg - P*sin(θ)
  • Determine the frictional force using Fk = ukN
  • Set up the equation for net work done: Work_P + Work_friction = 0
  • Explore the implications of varying the angle of force application on the required magnitude of P
USEFUL FOR

Physics students, engineers, and anyone involved in mechanics or force analysis will benefit from this discussion.

eanderson
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A 109-kg crate is being pushed across a horizontal floor by a force P that makes an angle of 38.3 ° below the horizontal. The coefficient of kinetic friction is 0.260. What should be the magnitude of P, so that the net work done by it and the kinetic frictional force is zero?
 
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Fk = ukN...
 
Suppose the box travels a distance d horizontally... then what is the work done by the force P ?
 

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