Kinetic Friction Between Block and Surface (HW Check)

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SUMMARY

The discussion focuses on calculating the coefficient of kinetic friction between a block and surface after a bullet is fired into the block. The problem involves a 10 g bullet traveling at 200 m/s colliding with a 1 kg block, which then slides 2 m on a horizontal surface. The conservation of momentum and work-energy principles are applied, leading to the conclusion that the coefficient of kinetic friction (M_K) is 0.1. The initial momentum of the bullet and the block's subsequent motion are critical to solving the problem accurately.

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  • Understanding of conservation of momentum
  • Familiarity with kinetic friction concepts
  • Knowledge of work-energy principles
  • Basic algebra for solving equations
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  • Learn about kinetic friction and its calculation methods
  • Explore work-energy theorem applications in physics
  • Review problem-solving techniques for dynamics involving multiple objects
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for examples of kinetic friction and momentum conservation in real-world applications.

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Homework Statement


A 10 g bullet is fired at 200 m/s into a 1 kg block after which they slide together 2 m on a horizontal surface. Determine the coefficient of kinetic friction between the block and surface.

Homework Equations


##M_AV_{Ai} + M_BV_{Bi} = 0##
##WNC = ΔE##

The Attempt at a Solution


##0.010(200) + V_{Bi} = 0##
##2 + V_{Bi} = 0##
##V_{Bi} = -2##

##-FKX = PE_f - PE_i##
##-M_KFNX = 0 - 1/2MV_i^2##
##-M_KMGX = 1/2MV_i^2##
##X = V_i^2/2M_Kg##
##2 = 2^2/2(10)M_K##
##20M_K = 2##
##M_K = 0.1##

Does this seem correct?
 
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Your first equation says that the total momentum is zero. Is the bullet not moving while the block is stationary before the collision? What's the total momentum that is conserved while the bullet becomes embedded in the block?

You need to rethink this.
 

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