Masrat_A
Homework Statement
During a vertical fall, a block's speed increases from 6 m/s to 8m/s over a 3 m distance. What percentage of the block's energy is dissipated due to air resistance over this distance?
Homework Equations
##E_f = E_i##
The Attempt at a Solution
##E_f = DE_i##
##KE_f + PE_f = D(KE_i + PE_i)##
##1/2MV_f^2 + 0 = D(1/2MV_i^2 + Mgy)##
##V_f^2 = D(V_i^2 + 2gy)##
##64 = D(36 + 60)##
##D = 0.67##
##1 - 0.67 = 0.33##
##0.33 * 100 = 33##
I wasn't so sure on what to label dissipated energy, so I went with D. Does any of this seem reasonable?