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Kinetic/Potential Energy of Vehicle on Ramps

  1. Oct 12, 2007 #1
    1. The problem statement, all variables and given/known data
    Under the influence of gravity g, a vehicle with mass m and initial velocity v0, travels a distance d1 to the bottom of a frictionless ramp ("a" degrees above horizontal). It then begins to travel up a ramp ("b" degrees above horizontal) with friction coefficient u. What distance d2 will the vehicle travel up the second ramp before stopping? (use energy methods)

    2. The attempt at a solution
    The kinetic energy gained by the vehicle on the first ramp will be dissipated by the negative work of friction and gravity on the second ramp. Thus:

    Ek = Eg

    To find a general formula for d2, I found expressions for Ek at the bottom of the first ramp and Eg at the top of the second and set them equal to each other (v1 is the speed at the bottom of the first ramp):

    v1^2 = v0^2 + 2ad
    v1 = sqrt[ v0^2 + 2*d1*g*sin(a) ]

    Ek = 1/2m(v1)^2
    Ek = 1/2m[v0^2 + 2*d1*g*sin(a)]
    Ek = 1/2m(v0)^2 + d1*m*g*sin(a)

    (Wf is work performed by friction, Wg by gravity; Ff is force of friction)

    Eg = Wf + Wg
    Eg = d2(Ff + Fg)
    Eg = d2[u*m*g*cos(b) + m*g*sin(b)]
    Eg = d2*m*g[u*cos(b) + sin(b)]

    Ek = Eg
    1/2m(v0)^2 + d1*m*g*sin(a) = d2*m*g[u*cos(b) + sin(b)]
    d2 = [1/2(v0)^2 + d1*g*sin(a)] / [g(u*cos(b) + sin(b)]

    Thanks for any help!
     
  2. jcsd
  3. Oct 12, 2007 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Looks OK to me.
     
  4. Oct 12, 2007 #3
    Thanks :)
     
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