- #1
Kirchhoff's Laws and Circuit Equation Help Request
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SUMMARY
This discussion focuses on applying Kirchhoff's Laws to solve circuit equations, specifically using mesh analysis to calculate potential differences and current relationships in electrical circuits. The key equations derived include the relationships i1 = i2 = i6 and the application of Kirchhoff's voltage law, resulting in the equation V + i1R + i7R = 0. The participants clarify that currents i3 and i4 are equal to i5, and that additional equations can be formed by analyzing the loops and nodes in the circuit.
PREREQUISITES- Understanding of Kirchhoff's Voltage Law (KVL)
- Familiarity with mesh analysis techniques
- Basic knowledge of electrical circuit components (resistors, voltage sources)
- Ability to manipulate algebraic equations for circuit analysis
- Study Kirchhoff's Current Law (KCL) for comprehensive circuit analysis
- Learn advanced mesh analysis techniques for complex circuits
- Explore practical applications of Kirchhoff's Laws in real-world circuits
- Review the concept of short circuits and their impact on circuit behavior
Electrical engineering students, circuit designers, and anyone involved in analyzing or designing electrical circuits will benefit from this discussion.
- #2
tiny-tim
Science Advisor
Homework Helper
- 25,837
- 258
hi sozener1! 
hint: the eg top-right-hand corner is also a node, and has one current going in and one current going out
sozener1 said:
hint: the eg top-right-hand corner is also a node, and has one current going in and one current going out
sooo … ? 
- #3
gneill
Mentor
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Note: Thread title changed to make it more descriptive of the thread content.
- #4
mr_pavlo
- 13
- 2
Hi,
actually you need only one more equation, since i1=i2, i3=i4 and i6 and i5 can be omited because they make no potential difference since they flow through short circuit.
So the last equation is 0=i3 x R + i3 x R - i7 x R
actually you need only one more equation, since i1=i2, i3=i4 and i6 and i5 can be omited because they make no potential difference since they flow through short circuit.
So the last equation is 0=i3 x R + i3 x R - i7 x R
- #5
Rellek
- 107
- 13
Hey there! It looks like this problem is just a use of mesh analysis without explicitly stating it.
So, if you look at the loop of wire that has the voltage source connected to it in series, you know that the current in that loop of wire must be constant. This is a fundamental principle of current.
What can you get from this? Well, it looks like i1 = i2 = i6
Not only this, but on the strand of wire on the right, this same principle can be applied.
If you use Kirchoff's voltage law around the first loop of wire on the left, you can see that:
(Going in defined direction of current) = V+i1R+i7R = 0, also, I think they made a mistake or misused the notation, because the shorter side of a voltage source is supposed to be the negative end.
From there, notice that i7 would have to be the net current between i1 and i3, and use the voltage rule around your second strand of wire in order to form another equation. After that, it is purely substitution, and assuming those R values are all equal, you'll have a nice result.
So, if you look at the loop of wire that has the voltage source connected to it in series, you know that the current in that loop of wire must be constant. This is a fundamental principle of current.
What can you get from this? Well, it looks like i1 = i2 = i6
Not only this, but on the strand of wire on the right, this same principle can be applied.
If you use Kirchoff's voltage law around the first loop of wire on the left, you can see that:
(Going in defined direction of current) = V+i1R+i7R = 0, also, I think they made a mistake or misused the notation, because the shorter side of a voltage source is supposed to be the negative end.
From there, notice that i7 would have to be the net current between i1 and i3, and use the voltage rule around your second strand of wire in order to form another equation. After that, it is purely substitution, and assuming those R values are all equal, you'll have a nice result.
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