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Kirchoffs current law. Someone check to make sure its correct?

  1. Aug 30, 2006 #1
    In the picture.
     

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  2. jcsd
  3. Aug 31, 2006 #2
    Due to the series configuration, Ic and Id are equal in magnitude but opposite in direction.
    if Ia = 3A, Ic = 1A, then Id = -1A
    Ia + Ic - Id - Ib = 0
    3A + 1A - 1A - Ib = 0
    as a result, Ia=Ib = 3A
     
  4. Aug 31, 2006 #3

    I agree with the Ic Id sign. However, Using the Node with Ia and Ic entering and Ib leaving and using KCL. I get Ia+Ic-Ib=0 therefore Ia+Ic=Ib or 3A + 1A =4A
     
  5. Aug 31, 2006 #4
    You are right.
    for the node with Ib and Id entering, Ia leaving
    -Ia + Ib + Id = 0
    -3 + Ib + -1 = 0
    Ib =4A
     
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