How can you tell if the Klein-Gordan Hamiltonian, [tex]H=\int d^3 x \frac{1}{2}(\partial_t \phi \partial_t \phi+\nabla^2\phi+m^2\phi^2) [/tex] is time-independent? Don't you have to plug in the expression for the field to show this? But isn't the only way you know how the field evolves with time is through [tex]\partial_t \phi=i[H,\phi] [/tex], and in order to evaluate this you have to assume the Hamiltonian is independent of time to use the equal-time commutation relations?(adsbygoogle = window.adsbygoogle || []).push({});

**Physics Forums - The Fusion of Science and Community**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Klein-gordan Hamiltonian time-independent?

Loading...

Similar Threads for Klein gordan Hamiltonian | Date |
---|---|

I What basically is Klein tunneling ? | Apr 15, 2018 |

A Coulomb Klein Gordon: Where does e^(-iEt) come from? | Apr 8, 2018 |

Why must Klein-Gordan equation describe spinless particles. | Jan 16, 2011 |

Klein gordan equation in electromagnetic potential | Feb 10, 2009 |

Klein-gordan eqn | Aug 15, 2008 |

**Physics Forums - The Fusion of Science and Community**