Calculating Velocity and Time of a Horizontal Projectile

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SUMMARY

The discussion focuses on calculating the time a rock is in the air and its initial velocity when thrown horizontally from a height of 50 meters. The correct time of flight is determined to be approximately 3.194 seconds, validated by the online platform WebAssign. The horizontal distance covered is 70 meters, and the calculations involve using the kinematic equations for projectile motion, specifically the equation for vertical displacement under constant acceleration due to gravity.

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  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion concepts
  • Familiarity with algebraic manipulation of equations
  • Basic understanding of gravitational acceleration (9.8 m/s²)
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  • Study the derivation of the kinematic equations for projectile motion
  • Learn how to apply the equations of motion to solve for horizontal and vertical components separately
  • Explore the concept of initial velocity in horizontal projectile motion
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Homework Statement



A person throws a rock horizontally from the roof of a 50m building. The rock lands 70 m from the base of the building.
How long was the rock in the air in s?

I got 3.194. The online home work thingy (webassign) said I was right.

With what velocity was the rock thrown in m/s?


Homework Equations


I used the Xf equation and solved for time. Dont I just plug in the time i got in the last equation and actualy solve it? Well i tryed that but I just keep getting it wrong.


The Attempt at a Solution


70=-4.9(3.194)^2 + Vo(3.194) Is this right?
 
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The way you need to set it up is imagine the rock is simply dropping because the x velocity doesn't matter. So s = vt + 1/2 at^2 s = 50m v = 0 a = 9.8m/s^2
 
50 = 0t + 1/2 9.8 t^2
 
djeitnstine said:
The way you need to set it up is imagine the rock is simply dropping because the x velocity doesn't matter. So s = vt + 1/2 at^2 s = 50m v = 0 a = 9.8m/s^2
what does s represent in this?
 
I think i did my algebra wrong because it said it was wrong.

(49.88+50)/3.194= 31.305
 
sorry s is displacement
 
50 = 0t + 1/2 9.8 t^2 this is the equation, the height 50 is equal to zero plus 1/2 9.8*t^2 (the rock is modeled as only dropping from 50 meters above the ground the x velocity has nothing to do with it)
 

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